What are the solutions to the equation y^2-6y=-7 ?

The solutions to the equation y^2-6y=-7 are y=3+sqrt(2),y=3-sqrt(2)

Find the zeros of y^2-6y=-7

The zeros of y^2-6y=-7 are y=3+sqrt(2),y=3-sqrt(2)

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y^{2} - 6 y = - 7

y = 3 + 2, y = 3 - 2

Solution steps

y^{2} - 6 y = - 7

Move

7

to the left side

y^{2} - 6 y + 7 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 7 = 22

y_{1, 2} = \frac{- ( - 6 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 6 ) + 2 2}{2 \cdot 1}, y_{2} = \frac{- ( - 6 ) - 2 2}{2 \cdot 1}

y = \frac{- ( - 6 ) + 2 2}{2 \cdot 1} : 3 + 2

y = \frac{- ( - 6 ) - 2 2}{2 \cdot 1} : 3 - 2

The solutions to the quadratic equation are:

y = 3 + 2, y = 3 - 2

- \frac{1}{2} (2) - 1

\frac{r}{3} > 6

- 3 x - 6 \leq - x + 2 < - 3 x + 6

4 x^{2} = 4 x - 1

\frac{11}{12} = \frac{3}{8} + v

What are the solutions to the equation y^2-6y=-7 ?
The solutions to the equation y^2-6y=-7 are y=3+sqrt(2),y=3-sqrt(2)
Find the zeros of y^2-6y=-7
The zeros of y^2-6y=-7 are y=3+sqrt(2),y=3-sqrt(2)