What are the solutions to the equation u^2-5u-6=0 ?

The solutions to the equation u^2-5u-6=0 are u=6,u=-1

Find the zeros of u^2-5u-6=0

The zeros of u^2-5u-6=0 are u=6,u=-1

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u^{2} - 5 u - 6 = 0

u = 6, u = - 1

Solution steps

u^{2} - 5 u - 6 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 6) = 7

u_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 1}, u_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 1}

u = \frac{- ( - 5 ) + 7}{2 \cdot 1} : 6

u = \frac{- ( - 5 ) - 7}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

u = 6, u = - 1

3 g \geq 9

\frac{y}{3} - 9 = 5

x^{2} - 11 x y + 24 y^{2}

15 x^{2} - 50 = - 19 x

52 - 3 x < - 14

What are the solutions to the equation u^2-5u-6=0 ?
The solutions to the equation u^2-5u-6=0 are u=6,u=-1
Find the zeros of u^2-5u-6=0
The zeros of u^2-5u-6=0 are u=6,u=-1