What are the solutions to the equation x(2x-3)-3(5-x)=83 ?

The solutions to the equation x(2x-3)-3(5-x)=83 are x=7,x=-7

Find the zeros of x(2x-3)-3(5-x)=83

The zeros of x(2x-3)-3(5-x)=83 are x=7,x=-7

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x (2 x - 3) - 3 (5 - x) = 83

x = 7, x = - 7

Solution steps

x (2 x - 3) - 3 (5 - x) = 83

Expand

x (2 x - 3) - 3 (5 - x) : 2 x^{2} - 15

2 x^{2} - 15 = 83

Move

83

to the left side

2 x^{2} - 98 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 2 ( - 98 )}{2 \cdot 2}

0^{2} - 4 \cdot 2 (- 98) = 28

x_{1, 2} = \frac{- 0 \pm 28}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 0 + 28}{2 \cdot 2}, x_{2} = \frac{- 0 - 28}{2 \cdot 2}

x = \frac{- 0 + 28}{2 \cdot 2} : 7

x = \frac{- 0 - 28}{2 \cdot 2} : - 7

The solutions to the quadratic equation are:

x = 7, x = - 7

5 (x + 6) - (5 x + 30) = 0

\frac{b}{3} + 5 = 9

3 (6 x + 4) = 2 x

100000 0^{\frac{1}{6}}

1 2^{2} + 8^{2} = x^{2}

What are the solutions to the equation x(2x-3)-3(5-x)=83 ?
The solutions to the equation x(2x-3)-3(5-x)=83 are x=7,x=-7
Find the zeros of x(2x-3)-3(5-x)=83
The zeros of x(2x-3)-3(5-x)=83 are x=7,x=-7