What are the solutions to the equation 12^2+8^2=x^2 ?

The solutions to the equation 12^2+8^2=x^2 are x=4sqrt(13),x=-4sqrt(13)

Find the zeros of 12^2+8^2=x^2

The zeros of 12^2+8^2=x^2 are x=4sqrt(13),x=-4sqrt(13)

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1 2^{2} + 8^{2} = x^{2}

x = 413, x = - 413

Decimal

x = 14.42220 \dots, x = - 14.42220 \dots

Solution steps

1 2^{2} + 8^{2} = x^{2}

Switch sides

x^{2} = 1 2^{2} + 8^{2}

Simplify

1 2^{2} + 8^{2} : 208

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 208, x = - 208

208 = 413

- 208 = - 413

x = 413, x = - 413

4 x - 2 = 0

- 49 b^{12} + a^{10}

\frac{4 x ^{- 2} ( yz ) ^{- 1}}{2 ^{3} x ^{4} y}

\frac{x ^{- 5}}{x ^{4}}

2 x^{2} + 2 x + 6 = 0

What are the solutions to the equation 12^2+8^2=x^2 ?
The solutions to the equation 12^2+8^2=x^2 are x=4sqrt(13),x=-4sqrt(13)
Find the zeros of 12^2+8^2=x^2
The zeros of 12^2+8^2=x^2 are x=4sqrt(13),x=-4sqrt(13)