What are the solutions to the equation (3x-8)^2+16=0 ?

The solutions to the equation (3x-8)^2+16=0 are x= 8/3+i 4/3 ,x= 8/3-i 4/3

Find the zeros of (3x-8)^2+16=0

The zeros of (3x-8)^2+16=0 are x= 8/3+i 4/3 ,x= 8/3-i 4/3

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(3 x - 8)^{2} + 16 = 0

x = \frac{8}{3} + i \frac{4}{3}, x = \frac{8}{3} - i \frac{4}{3}

Solution steps

(3 x - 8)^{2} + 16 = 0

Move

16

to the right side

(3 x - 8)^{2} = - 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 8 = - 16 : x = \frac{8}{3} + i \frac{4}{3}

Solve

3 x - 8 = - - 16 : x = \frac{8}{3} - i \frac{4}{3}

The solutions to the quadratic equation are:

x = \frac{8}{3} + i \frac{4}{3}, x = \frac{8}{3} - i \frac{4}{3}

- 3 x^{2} - 2 x + 7 = 0

(x - 3)^{\frac{7}{2}} - 9 (x - 3)^{\frac{3}{2}}

\frac{x + 2}{x + 3} < 0

a^{2} - b^{2} + 4 a - 4 b

r > 15 - 2 r

What are the solutions to the equation (3x-8)^2+16=0 ?
The solutions to the equation (3x-8)^2+16=0 are x= 8/3+i 4/3 ,x= 8/3-i 4/3
Find the zeros of (3x-8)^2+16=0
The zeros of (3x-8)^2+16=0 are x= 8/3+i 4/3 ,x= 8/3-i 4/3