What are the solutions to the equation -4x^2+19x=-30 ?

The solutions to the equation -4x^2+19x=-30 are x=-5/4 ,x=6

Find the zeros of -4x^2+19x=-30

The zeros of -4x^2+19x=-30 are x=-5/4 ,x=6

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- 4 x^{2} + 19 x = - 30

x = - \frac{5}{4}, x = 6

Decimal Notation

x = - 1.25, x = 6

Solution steps

- 4 x^{2} + 19 x = - 30

Move

30

to the left side

- 4 x^{2} + 19 x + 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 ( - 4 ) \cdot 30}{2 ( - 4 )}

1 9^{2} - 4 (- 4) \cdot 30 = 29

x_{1, 2} = \frac{- 19 \pm 29}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 19 + 29}{2 ( - 4 )}, x_{2} = \frac{- 19 - 29}{2 ( - 4 )}

x = \frac{- 19 + 29}{2 ( - 4 )} : - \frac{5}{4}

x = \frac{- 19 - 29}{2 ( - 4 )} : 6

The solutions to the quadratic equation are:

x = - \frac{5}{4}, x = 6

3 x - 42 > 3

\frac{a ^{12} b ^{- 3}}{( ab ) ^{- 4}}

- 4 x^{2} + 1 = 0

2 x^{2} + 3 x - 3 = 0

2 b^{4} - 6 b^{3} + 6 b^{2} - 2 b

What are the solutions to the equation -4x^2+19x=-30 ?
The solutions to the equation -4x^2+19x=-30 are x=-5/4 ,x=6
Find the zeros of -4x^2+19x=-30
The zeros of -4x^2+19x=-30 are x=-5/4 ,x=6