What is factor 2x^5-9x^4+12x^3-4x^2-8x+4 ?

The solution to factor 2x^5-9x^4+12x^3-4x^2-8x+4 is (2x-1)(x^2-2x+2)(x^2-2x-2)

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factor 2x^5-9x^4+12x^3-4x^2-8x+4

factor

2 x^{5} - 9 x^{4} + 12 x^{3} - 4 x^{2} - 8 x + 4

(2 x - 1) (x^{2} - 2 x + 2) (x^{2} - 2 x - 2)

Solution steps

2 x^{5} - 9 x^{4} + 12 x^{3} - 4 x^{2} - 8 x + 4

Use the rational root theorem

= (2 x - 1) \frac{2 x ^{5} - 9 x ^{4} + 12 x ^{3} - 4 x ^{2} - 8 x + 4}{2 x - 1}

\frac{2 x ^{5} - 9 x ^{4} + 12 x ^{3} - 4 x ^{2} - 8 x + 4}{2 x - 1} = x^{4} - 4 x^{3} + 4 x^{2} - 4

= (2 x - 1) (x^{4} - 4 x^{3} + 4 x^{2} - 4)

Factor

x^{4} - 4 x^{3} + 4 x^{2} - 4 : (x^{2} - 2 x + 2) (x^{2} - 2 x - 2)

= (2 x - 1) (x^{2} - 2 x + 2) (x^{2} - 2 x - 2)

3 x^{2} + 5 x - 9 = 0

8 = x^{2} - 8 x - 15

- 16 t^{2} + 50 t = 0

4 x^{2} - 200 = - 20

2 y^{2} + 10 y = - 7

What is factor 2x^5-9x^4+12x^3-4x^2-8x+4 ?
The solution to factor 2x^5-9x^4+12x^3-4x^2-8x+4 is (2x-1)(x^2-2x+2)(x^2-2x-2)