What are the solutions to the equation 10x^2+7x-12=0 ?

The solutions to the equation 10x^2+7x-12=0 are x= 4/5 ,x=-3/2

Find the zeros of 10x^2+7x-12=0

The zeros of 10x^2+7x-12=0 are x= 4/5 ,x=-3/2

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10 x^{2} + 7 x - 12 = 0

x = \frac{4}{5}, x = - \frac{3}{2}

Decimal Notation

x = 0.8, x = - 1.5

Solution steps

10 x^{2} + 7 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 10 ( - 12 )}{2 \cdot 10}

7^{2} - 4 \cdot 10 (- 12) = 23

x_{1, 2} = \frac{- 7 \pm 23}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 7 + 23}{2 \cdot 10}, x_{2} = \frac{- 7 - 23}{2 \cdot 10}

x = \frac{- 7 + 23}{2 \cdot 10} : \frac{4}{5}

x = \frac{- 7 - 23}{2 \cdot 10} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{4}{5}, x = - \frac{3}{2}

18 - x^{2} = 39

\frac{3 + 7 i}{i}

5^{2}

\frac{3 x + 5}{3} + \frac{x + 4}{2} \geq \frac{x + 3}{6}

∣ x - 4 ∣ - 4 = 5

What are the solutions to the equation 10x^2+7x-12=0 ?
The solutions to the equation 10x^2+7x-12=0 are x= 4/5 ,x=-3/2
Find the zeros of 10x^2+7x-12=0
The zeros of 10x^2+7x-12=0 are x= 4/5 ,x=-3/2