What are the solutions to the equation a^2-3a=10 ?

The solutions to the equation a^2-3a=10 are a=5,a=-2

Find the zeros of a^2-3a=10

The zeros of a^2-3a=10 are a=5,a=-2

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a^{2} - 3 a = 10

a = 5, a = - 2

Solution steps

a^{2} - 3 a = 10

Move

10

to the left side

a^{2} - 3 a - 10 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 10) = 7

a_{1, 2} = \frac{- ( - 3 ) \pm 7}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 3 ) + 7}{2 \cdot 1}, a_{2} = \frac{- ( - 3 ) - 7}{2 \cdot 1}

a = \frac{- ( - 3 ) + 7}{2 \cdot 1} : 5

a = \frac{- ( - 3 ) - 7}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

a = 5, a = - 2

12.0107 = (12 \cdot 0.9893) + x (0.0107)

- 3 a = - 7

x^{2} + 11 x = - 30

(4 x + 1) (2 x - 7) = 0

i^{- 203}

What are the solutions to the equation a^2-3a=10 ?
The solutions to the equation a^2-3a=10 are a=5,a=-2
Find the zeros of a^2-3a=10
The zeros of a^2-3a=10 are a=5,a=-2