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Popular >

factor 125a^6+1

Solution

factor

125 a^{6} + 1

Solution

(5 a^{2} + 1) (25 a^{4} - 5 a^{2} + 1)

Solution steps

125 a^{6} + 1

Apply exponent rules

= (5 a^{2})^{3} + 1^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(5 a^{2})^{3} + 1^{3} = (5 a^{2} + 1) (5^{2} a^{4} - 5 a^{2} + 1)

= (5 a^{2} + 1) (5^{2} a^{4} - 5 a^{2} + 1)

5^{2} = 25

= (5 a^{2} + 1) (25 a^{4} - 5 a^{2} + 1)

Popular Examples

factor ax^2-abx+x-b factor

a x^{2} - ab x + x - b

simplify (3/4 a^3-2/3 b^4)^2 simplify

(\frac{3}{4} a^{3} - \frac{2}{3} b^{4})^{2}

3 x^{2} + 1 = 54

4 y - 4 \geq 20

factor-6a^4b^4-6a^3b^5 factor

- 6 a^{4} b^{4} - 6 a^{3} b^{5}

Frequently Asked Questions (FAQ)

What is factor 125a^6+1 ?
The solution to factor 125a^6+1 is (5a^2+1)(25a^4-5a^2+1)