What are the solutions to the equation x^2+6+9=0 ?

The solutions to the equation x^2+6+9=0 are x=sqrt(15)i,x=-sqrt(15)i

Find the zeros of x^2+6+9=0

The zeros of x^2+6+9=0 are x=sqrt(15)i,x=-sqrt(15)i

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x^{2} + 6 + 9 = 0

x = 15 i, x = - 15 i

Solution steps

x^{2} + 6 + 9 = 0

Move

6

to the right side

x^{2} + 9 = - 6

Move

9

to the right side

x^{2} = - 15

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 15, x = - - 15

- 15 = 15 i

- - 15 = - 15 i

x = 15 i, x = - 15 i

(\frac{2 x}{3 ( x ^{2} ) ^{\frac{2}{3}}})^{2}

2 j^{2} + 9 j + 7

x - 7.6 (0.9 x + 1) \leq 5.6 (1 + 1.1 x)

\frac{1}{x - 4} \geq \frac{3}{x + 1}

What are the solutions to the equation x^2+6+9=0 ?
The solutions to the equation x^2+6+9=0 are x=sqrt(15)i,x=-sqrt(15)i
Find the zeros of x^2+6+9=0
The zeros of x^2+6+9=0 are x=sqrt(15)i,x=-sqrt(15)i