What are the solutions to the equation (x^2)/4-5x+17=0 ?

The solutions to the equation (x^2)/4-5x+17=0 are x=2(5+2sqrt(2)),x=2(5-2sqrt(2))

Find the zeros of (x^2)/4-5x+17=0

The zeros of (x^2)/4-5x+17=0 are x=2(5+2sqrt(2)),x=2(5-2sqrt(2))

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\frac{x ^{2}}{4} - 5 x + 17 = 0

x = 2 (5 + 22), x = 2 (5 - 22)

Decimal Notation

x = 15.65685 \dots, x = 4.34314 \dots

Solution steps

\frac{x ^{2}}{4} - 5 x + 17 = 0

Multiply both sides by

4

x^{2} - 20 x + 68 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot 68}{2 \cdot 1}

(- 20)^{2} - 4 \cdot 1 \cdot 68 = 82

x_{1, 2} = \frac{- ( - 20 ) \pm 8 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 8 2}{2 \cdot 1}, x_{2} = \frac{- ( - 20 ) - 8 2}{2 \cdot 1}

x = \frac{- ( - 20 ) + 8 2}{2 \cdot 1} : 2 (5 + 22)

x = \frac{- ( - 20 ) - 8 2}{2 \cdot 1} : 2 (5 - 22)

The solutions to the quadratic equation are:

x = 2 (5 + 22), x = 2 (5 - 22)

\frac{2}{5} - 2

x - 8 > 5 x + 3

(50 - 2 x) (40 - 2 x) = 875

n^{2} + 2 n - 2 = 0

x^{12} y^{18} + 1

What are the solutions to the equation (x^2)/4-5x+17=0 ?
The solutions to the equation (x^2)/4-5x+17=0 are x=2(5+2sqrt(2)),x=2(5-2sqrt(2))
Find the zeros of (x^2)/4-5x+17=0
The zeros of (x^2)/4-5x+17=0 are x=2(5+2sqrt(2)),x=2(5-2sqrt(2))