What are the solutions to the equation 5-5x=(3x+4)(x-1) ?

The solutions to the equation 5-5x=(3x+4)(x-1) are x=1,x=-3

Find the zeros of 5-5x=(3x+4)(x-1)

The zeros of 5-5x=(3x+4)(x-1) are x=1,x=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 - 5 x = (3 x + 4) (x - 1)

x = 1, x = - 3

Solution steps

5 - 5 x = (3 x + 4) (x - 1)

Expand

(3 x + 4) (x - 1) : 3 x^{2} + x - 4

5 - 5 x = 3 x^{2} + x - 4

Switch sides

3 x^{2} + x - 4 = 5 - 5 x

Move

5 x

to the left side

3 x^{2} + 6 x - 4 = 5

Move

5

to the left side

3 x^{2} + 6 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 ( - 9 )}{2 \cdot 3}

6^{2} - 4 \cdot 3 (- 9) = 12

x_{1, 2} = \frac{- 6 \pm 12}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 6 + 12}{2 \cdot 3}, x_{2} = \frac{- 6 - 12}{2 \cdot 3}

x = \frac{- 6 + 12}{2 \cdot 3} : 1

x = \frac{- 6 - 12}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

x = 1, x = - 3

(5 y + 7) (8 + y) = 0

\frac{9 ( x - 2 )}{4} - \frac{7 ( x - 1 )}{3} = 6 x + 1

6108

14 x^{2} + 31 x + 15

x^{3} + 2 x^{2} - 4 x - 8

What are the solutions to the equation 5-5x=(3x+4)(x-1) ?
The solutions to the equation 5-5x=(3x+4)(x-1) are x=1,x=-3
Find the zeros of 5-5x=(3x+4)(x-1)
The zeros of 5-5x=(3x+4)(x-1) are x=1,x=-3