What are the solutions to the equation (3x-4)^2=64 ?

The solutions to the equation (3x-4)^2=64 are x=4,x=-4/3

Find the zeros of (3x-4)^2=64

The zeros of (3x-4)^2=64 are x=4,x=-4/3

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(3 x - 4)^{2} = 64

x = 4, x = - \frac{4}{3}

Solution steps

(3 x - 4)^{2} = 64

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 4 = 64 : x = 4

Solve

3 x - 4 = - 64 : x = - \frac{4}{3}

The solutions to the quadratic equation are:

x = 4, x = - \frac{4}{3}

- (\frac{2}{5})^{2}

7 p^{2} = - 40 p - 25

5 n^{2} - 80

\frac{2}{5} + \frac{2}{5}

\frac{2 π}{4 π}

What are the solutions to the equation (3x-4)^2=64 ?
The solutions to the equation (3x-4)^2=64 are x=4,x=-4/3
Find the zeros of (3x-4)^2=64
The zeros of (3x-4)^2=64 are x=4,x=-4/3