What is factor u^9-s^9 ?

The solution to factor u^9-s^9 is (u-s)(u^2+us+s^2)(u^6+u^3s^3+s^6)

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factor u^9-s^9

factor

u^{9} - s^{9}

(u - s) (u^{2} + u s + s^{2}) (u^{6} + u^{3} s^{3} + s^{6})

Solution steps

u^{9} - s^{9}

Apply exponent rules

= (u^{3})^{3} - (s^{3})^{3}

Apply Difference of Cubes Formula:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

(u^{3})^{3} - (s^{3})^{3} = (u^{3} - s^{3}) ((u^{3})^{2} + u^{3} s^{3} + (s^{3})^{2})

= (u^{3} - s^{3}) ((u^{3})^{2} + u^{3} s^{3} + (s^{3})^{2})

Simplify

(u^{3})^{2} + u^{3} s^{3} + (s^{3})^{2} : u^{6} + u^{3} s^{3} + s^{6}

= (u^{3} - s^{3}) (u^{6} + u^{3} s^{3} + s^{6})

Factor

u^{3} - s^{3} : (u - s) (u^{2} + u s + s^{2})

= (u - s) (u^{2} + u s + s^{2}) (u^{6} + u^{3} s^{3} + s^{6})

\frac{x - 1}{3} + \frac{2 x + 1}{5} = \frac{3 x - 1}{4}

4 x^{2} + 4 = 0

\frac{x - 6}{x + 2} \geq 0

(x - y)^{2} + 4 (x - y) + 3

What is factor u^9-s^9 ?
The solution to factor u^9-s^9 is (u-s)(u^2+us+s^2)(u^6+u^3s^3+s^6)