What is factor 3j^2+8j-3 ?

The solution to factor 3j^2+8j-3 is (3j-1)(j+3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 3j^2+8j-3

factor

3 j^{2} + 8 j - 3

(3 j - 1) (j + 3)

Solution steps

3 j^{2} + 8 j - 3

Break the expression into groups

= (3 j^{2} - j) + (9 j - 3)

Factor out

j

from

3 j^{2} - j : j (3 j - 1)

Factor out

3

from

9 j - 3 : 3 (3 j - 1)

= j (3 j - 1) + 3 (3 j - 1)

Factor out common term

3 j - 1

= (3 j - 1) (j + 3)

x^{2} - 16 x = - 68

3 x (x - 6) = 0

\frac{2}{( 2 + 1 ) ^{3}}

\frac{- 48}{- 6}

e^{l n (8)}