What are the solutions to the equation x^2-2x+24=0 ?

The solutions to the equation x^2-2x+24=0 are x=1+sqrt(23)i,x=1-sqrt(23)i

Find the zeros of x^2-2x+24=0

The zeros of x^2-2x+24=0 are x=1+sqrt(23)i,x=1-sqrt(23)i

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x^{2} - 2 x + 24 = 0

x = 1 + 23 i, x = 1 - 23 i

Solution steps

x^{2} - 2 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 24 : 223 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 23 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 23 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 23 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 23 i}{2 \cdot 1} : 1 + 23 i

x = \frac{- ( - 2 ) - 2 23 i}{2 \cdot 1} : 1 - 23 i

The solutions to the quadratic equation are:

x = 1 + 23 i, x = 1 - 23 i

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∣ 2 x - 3 ∣ < 4

a^{2} - b^{2} - 2 a - 2 b

x^{2} - 12 x - 45 = 0

What are the solutions to the equation x^2-2x+24=0 ?
The solutions to the equation x^2-2x+24=0 are x=1+sqrt(23)i,x=1-sqrt(23)i
Find the zeros of x^2-2x+24=0
The zeros of x^2-2x+24=0 are x=1+sqrt(23)i,x=1-sqrt(23)i