What are the solutions to the equation x^2-12x-45=0 ?

The solutions to the equation x^2-12x-45=0 are x=15,x=-3

Find the zeros of x^2-12x-45=0

The zeros of x^2-12x-45=0 are x=15,x=-3

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x^{2} - 12 x - 45 = 0

x = 15, x = - 3

Solution steps

x^{2} - 12 x - 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot ( - 45 )}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot (- 45) = 18

x_{1, 2} = \frac{- ( - 12 ) \pm 18}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 18}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 18}{2 \cdot 1}

x = \frac{- ( - 12 ) + 18}{2 \cdot 1} : 15

x = \frac{- ( - 12 ) - 18}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 15, x = - 3

5 x = 2 x^{2} + 1

4 b^{2} - 19 b + 17 = 0

x^{3} - 4 x^{4}

∣ 2 x - 8 ∣ > 6

\frac{2 x - 1}{1 - x} > 3

What are the solutions to the equation x^2-12x-45=0 ?
The solutions to the equation x^2-12x-45=0 are x=15,x=-3
Find the zeros of x^2-12x-45=0
The zeros of x^2-12x-45=0 are x=15,x=-3