What are the solutions to the equation 3(x-7)^2+2=29 ?

The solutions to the equation 3(x-7)^2+2=29 are x=10,x=4

Find the zeros of 3(x-7)^2+2=29

The zeros of 3(x-7)^2+2=29 are x=10,x=4

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3 (x - 7)^{2} + 2 = 29

x = 10, x = 4

Solution steps

3 (x - 7)^{2} + 2 = 29

Move

2

to the right side

3 (x - 7)^{2} = 27

Divide both sides by

3

(x - 7)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 7 = 9 : x = 10

Solve

x - 7 = - 9 : x = 4

The solutions to the quadratic equation are:

x = 10, x = 4

8 y^{4} + 20 y^{3} + 8 y^{2}

2 i^{4}

3 x^{2} + 6 x - 24 x - 48

3 m^{2} - m - 30

2 t - 3 > - 3 and 5 t - \frac{4}{5} > 8

What are the solutions to the equation 3(x-7)^2+2=29 ?
The solutions to the equation 3(x-7)^2+2=29 are x=10,x=4
Find the zeros of 3(x-7)^2+2=29
The zeros of 3(x-7)^2+2=29 are x=10,x=4