What are the solutions to the equation 3(x+1)^2+x=-7 ?

The solutions to the equation 3(x+1)^2+x=-7 are x=-7/6+i(sqrt(71))/6 ,x=-7/6-i(sqrt(71))/6

Find the zeros of 3(x+1)^2+x=-7

The zeros of 3(x+1)^2+x=-7 are x=-7/6+i(sqrt(71))/6 ,x=-7/6-i(sqrt(71))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 (x + 1)^{2} + x = - 7

x = - \frac{7}{6} + i \frac{71}{6}, x = - \frac{7}{6} - i \frac{71}{6}

Solution steps

3 (x + 1)^{2} + x = - 7

Expand

3 (x + 1)^{2} + x : 3 x^{2} + 7 x + 3

3 x^{2} + 7 x + 3 = - 7

Move

7

to the left side

3 x^{2} + 7 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 3 \cdot 10}{2 \cdot 3}

Simplify

7^{2} - 4 \cdot 3 \cdot 10 : 71 i

x_{1, 2} = \frac{- 7 \pm 71 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 7 + 71 i}{2 \cdot 3}, x_{2} = \frac{- 7 - 71 i}{2 \cdot 3}

x = \frac{- 7 + 71 i}{2 \cdot 3} : - \frac{7}{6} + i \frac{71}{6}

x = \frac{- 7 - 71 i}{2 \cdot 3} : - \frac{7}{6} - i \frac{71}{6}

The solutions to the quadratic equation are:

x = - \frac{7}{6} + i \frac{71}{6}, x = - \frac{7}{6} - i \frac{71}{6}

\frac{1}{2} (4 x - 4) - \frac{2}{3} (6 x + 9) \leq 7

∣ 2 x - 2 ∣ = 8

3 x^{2} + 17 x + 14 = 0

e^{\frac{9}{2}}

360 - 10 t^{2}

What are the solutions to the equation 3(x+1)^2+x=-7 ?
The solutions to the equation 3(x+1)^2+x=-7 are x=-7/6+i(sqrt(71))/6 ,x=-7/6-i(sqrt(71))/6
Find the zeros of 3(x+1)^2+x=-7
The zeros of 3(x+1)^2+x=-7 are x=-7/6+i(sqrt(71))/6 ,x=-7/6-i(sqrt(71))/6