What are the solutions to the equation 0=-3x^2+9x-4 ?

The solutions to the equation 0=-3x^2+9x-4 are x=(9-sqrt(33))/6 ,x=(9+sqrt(33))/6

Find the zeros of 0=-3x^2+9x-4

The zeros of 0=-3x^2+9x-4 are x=(9-sqrt(33))/6 ,x=(9+sqrt(33))/6

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0 = - 3 x^{2} + 9 x - 4

x = \frac{9 - 33}{6}, x = \frac{9 + 33}{6}

Decimal Notation

x = 0.54257 \dots, x = 2.45742 \dots

Solution steps

0 = - 3 x^{2} + 9 x - 4

Switch sides

- 3 x^{2} + 9 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 3 ) ( - 4 )}{2 ( - 3 )}

9^{2} - 4 (- 3) (- 4) = 33

x_{1, 2} = \frac{- 9 \pm 33}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 9 + 33}{2 ( - 3 )}, x_{2} = \frac{- 9 - 33}{2 ( - 3 )}

x = \frac{- 9 + 33}{2 ( - 3 )} : \frac{9 - 33}{6}

x = \frac{- 9 - 33}{2 ( - 3 )} : \frac{9 + 33}{6}

The solutions to the quadratic equation are:

x = \frac{9 - 33}{6}, x = \frac{9 + 33}{6}

\frac{8 ^{5}}{8 ^{2}}

- 4 (3 - 2 x) \leq - (x + 20)

x^{2} + 16 x + 43 = 0

2 x^{2} - 3 x - 2 = 0

3 b^{2} + 8 b + 4 = 0

What are the solutions to the equation 0=-3x^2+9x-4 ?
The solutions to the equation 0=-3x^2+9x-4 are x=(9-sqrt(33))/6 ,x=(9+sqrt(33))/6
Find the zeros of 0=-3x^2+9x-4
The zeros of 0=-3x^2+9x-4 are x=(9-sqrt(33))/6 ,x=(9+sqrt(33))/6