What are the solutions to the equation 4a^2-14a=-50 ?

The solutions to the equation 4a^2-14a=-50 are a= 7/4+i(sqrt(151))/4 ,a= 7/4-i(sqrt(151))/4

Find the zeros of 4a^2-14a=-50

The zeros of 4a^2-14a=-50 are a= 7/4+i(sqrt(151))/4 ,a= 7/4-i(sqrt(151))/4

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4 a^{2} - 14 a = - 50

a = \frac{7}{4} + i \frac{151}{4}, a = \frac{7}{4} - i \frac{151}{4}

Solution steps

4 a^{2} - 14 a = - 50

Move

50

to the left side

4 a^{2} - 14 a + 50 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 4 \cdot 50}{2 \cdot 4}

Simplify

(- 14)^{2} - 4 \cdot 4 \cdot 50 : 2151 i

a_{1, 2} = \frac{- ( - 14 ) \pm 2 151 i}{2 \cdot 4}

Separate the solutions

a_{1} = \frac{- ( - 14 ) + 2 151 i}{2 \cdot 4}, a_{2} = \frac{- ( - 14 ) - 2 151 i}{2 \cdot 4}

a = \frac{- ( - 14 ) + 2 151 i}{2 \cdot 4} : \frac{7}{4} + i \frac{151}{4}

a = \frac{- ( - 14 ) - 2 151 i}{2 \cdot 4} : \frac{7}{4} - i \frac{151}{4}

The solutions to the quadratic equation are:

a = \frac{7}{4} + i \frac{151}{4}, a = \frac{7}{4} - i \frac{151}{4}

(3^{2})^{- 1}

4 a^{2} + 60 a + 224 = 0

(\frac{4 y + 5}{8 x + 9})^{2}

x^{2} = 3

8 m^{2} + 20 m + 13 = 0

What are the solutions to the equation 4a^2-14a=-50 ?
The solutions to the equation 4a^2-14a=-50 are a= 7/4+i(sqrt(151))/4 ,a= 7/4-i(sqrt(151))/4
Find the zeros of 4a^2-14a=-50
The zeros of 4a^2-14a=-50 are a= 7/4+i(sqrt(151))/4 ,a= 7/4-i(sqrt(151))/4