What are the solutions to the equation x^2+4x-77=0 ?

The solutions to the equation x^2+4x-77=0 are x=7,x=-11

Find the zeros of x^2+4x-77=0

The zeros of x^2+4x-77=0 are x=7,x=-11

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x^{2} + 4 x - 77 = 0

x = 7, x = - 11

Solution steps

x^{2} + 4 x - 77 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 77 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 77) = 18

x_{1, 2} = \frac{- 4 \pm 18}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 18}{2 \cdot 1}, x_{2} = \frac{- 4 - 18}{2 \cdot 1}

x = \frac{- 4 + 18}{2 \cdot 1} : 7

x = \frac{- 4 - 18}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

x = 7, x = - 11

9 x^{2} + 21 x - 8 = 0

5 x - 19 \leq 1

u^{2} - 6 u - 7

7 w + 4 - 3 w = 15

s^{2} + 10 s + 21 = 0

What are the solutions to the equation x^2+4x-77=0 ?
The solutions to the equation x^2+4x-77=0 are x=7,x=-11
Find the zeros of x^2+4x-77=0
The zeros of x^2+4x-77=0 are x=7,x=-11