What is \sqrt[6]{2}*sqrt(2^5) ?

The solution to \sqrt[6]{2}*sqrt(2^5) is 4\sqrt[3]{2^2}

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simplify \sqrt[6]{2}*sqrt(2^5)

simplify

Decimal Notation

6.34960 \dots

Solution steps

2^{5} = 42

Apply radical rule:

= 2^{\frac{1}{6}} \cdot 42

Apply radical rule:

a = a^{\frac{1}{2}}

2 = 2^{\frac{1}{2}}

= 2^{\frac{1}{6}} \cdot 4 \cdot 2^{\frac{1}{2}}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2^{\frac{1}{6}} \cdot 2^{\frac{1}{2}} = 2^{\frac{1}{6} + \frac{1}{2}}

= 2^{\frac{1}{6} + \frac{1}{2}} \cdot 4

\frac{1}{6} + \frac{1}{2} = \frac{2}{3}

= 2^{\frac{2}{3}} \cdot 4

3 x^{2} - 4 x + 4 = 0

0 = x^{2} + 4 x + 8

∣ 2 s + 1 ∣ + 3 \leq 2

3 x (5 x + 2) = 0

2 x^{5} + 2 x^{2} 2 y^{3} - 8 x^{3} - 8 y^{3}

What is \sqrt[6]{2}*sqrt(2^5) ?
The solution to \sqrt[6]{2}*sqrt(2^5) is 4\sqrt[3]{2^2}