What are the solutions to the equation -x^2+6x-6=0 ?

The solutions to the equation -x^2+6x-6=0 are x=3-sqrt(3),x=3+sqrt(3)

Find the zeros of -x^2+6x-6=0

The zeros of -x^2+6x-6=0 are x=3-sqrt(3),x=3+sqrt(3)

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- x^{2} + 6 x - 6 = 0

x = 3 - 3, x = 3 + 3

Decimal Notation

x = 1.26794 \dots, x = 4.73205 \dots

Solution steps

- x^{2} + 6 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 1 ) ( - 6 )}{2 ( - 1 )}

6^{2} - 4 (- 1) (- 6) = 23

x_{1, 2} = \frac{- 6 \pm 2 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 3}{2 ( - 1 )}, x_{2} = \frac{- 6 - 2 3}{2 ( - 1 )}

x = \frac{- 6 + 2 3}{2 ( - 1 )} : 3 - 3

x = \frac{- 6 - 2 3}{2 ( - 1 )} : 3 + 3

The solutions to the quadratic equation are:

x = 3 - 3, x = 3 + 3

\frac{1}{3} x = 6

y^{2} + 3 y - 10 = 0

(x + 5) (x + 1) = 0

7 + \frac{4 x}{9} = \frac{x}{2}

16 x^{2} + 25 = 40 x

What are the solutions to the equation -x^2+6x-6=0 ?
The solutions to the equation -x^2+6x-6=0 are x=3-sqrt(3),x=3+sqrt(3)
Find the zeros of -x^2+6x-6=0
The zeros of -x^2+6x-6=0 are x=3-sqrt(3),x=3+sqrt(3)