What are the solutions to the equation 16x^2+25=40x ?

The solutions to the equation 16x^2+25=40x are x= 5/4

Find the zeros of 16x^2+25=40x

The zeros of 16x^2+25=40x are x= 5/4

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16 x^{2} + 25 = 40 x

x = \frac{5}{4}

Decimal Notation

x = 1.25

Solution steps

16 x^{2} + 25 = 40 x

Move

40 x

to the left side

16 x^{2} + 25 - 40 x = 0

Write in the standard form

a x^{2} + b x + c = 0

16 x^{2} - 40 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 16 \cdot 25}{2 \cdot 16}

(- 40)^{2} - 4 \cdot 16 \cdot 25 = 0

x_{1, 2} = \frac{- ( - 40 ) \pm 0}{2 \cdot 16}

x = \frac{- ( - 40 )}{2 \cdot 16}

\frac{- ( - 40 )}{2 \cdot 16} = \frac{5}{4}

x = \frac{5}{4}

The solution to the quadratic equation is:

x = \frac{5}{4}

\frac{2 - x}{5 x + 10} > 0

- 3 \leq 2 x + 1 \leq - 2

4 y - 7 \geq 10

x^{2} - 24 x + 144 = 100

\frac{3}{4} \cdot \frac{5}{2}

What are the solutions to the equation 16x^2+25=40x ?
The solutions to the equation 16x^2+25=40x are x= 5/4
Find the zeros of 16x^2+25=40x
The zeros of 16x^2+25=40x are x= 5/4