What is (1/(xy)-1/(y^2))/(1/(x^2y)-1/(xy^2)) ?

The solution to (1/(xy)-1/(y^2))/(1/(x^2y)-1/(xy^2)) is x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (1/(xy)-1/(y^2))/(1/(x^2y)-1/(xy^2))

simplify

\frac{\frac{1}{x y} - \frac{1}{y ^{2}}}{\frac{1}{x ^{2} y} - \frac{1}{x y ^{2}}}

x

Solution steps

\frac{\frac{1}{x y} - \frac{1}{y ^{2}}}{\frac{1}{x ^{2} y} - \frac{1}{x y ^{2}}}

Join

\frac{1}{x y} - \frac{1}{y ^{2}} : \frac{y - x}{x y ^{2}}

= \frac{\frac{y - x}{x y ^{2}}}{\frac{1}{x ^{2} y} - \frac{1}{x y ^{2}}}

Join

\frac{1}{x ^{2} y} - \frac{1}{x y ^{2}} : \frac{y - x}{x ^{2} y ^{2}}

= \frac{\frac{y - x}{x y ^{2}}}{\frac{y - x}{x ^{2} y ^{2}}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( y - x ) x ^{2} y ^{2}}{x y ^{2} ( y - x )}

Cancel

\frac{( y - x ) x ^{2} y ^{2}}{x y ^{2} ( y - x )} : x

= x

\frac{3 - 6 i}{4 - 3 i}

- 2 x^{2} - 7 x - 5 = 0

32 a^{2} + 24 b^{2}

x^{2} + \frac{3}{4} = 0

\frac{3}{8} (2 x - 3) - \frac{4}{3} (x - 2) = \frac{2}{3}

What is (1/(xy)-1/(y^2))/(1/(x^2y)-1/(xy^2)) ?
The solution to (1/(xy)-1/(y^2))/(1/(x^2y)-1/(xy^2)) is x