What are the solutions to the equation x^2+3x-130=0 ?

The solutions to the equation x^2+3x-130=0 are x=10,x=-13

Find the zeros of x^2+3x-130=0

The zeros of x^2+3x-130=0 are x=10,x=-13

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x^{2} + 3 x - 130 = 0

x = 10, x = - 13

Solution steps

x^{2} + 3 x - 130 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 130 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 130) = 23

x_{1, 2} = \frac{- 3 \pm 23}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 23}{2 \cdot 1}, x_{2} = \frac{- 3 - 23}{2 \cdot 1}

x = \frac{- 3 + 23}{2 \cdot 1} : 10

x = \frac{- 3 - 23}{2 \cdot 1} : - 13

The solutions to the quadratic equation are:

x = 10, x = - 13

- 4 (3 v - 2) = 56

2 m^{2} + 10 = 210

\frac{3 + i 3}{3 - i 3}

- 1 \leq \frac{2 x - 3}{2} < 4

- 21 x - 6 x^{2}

What are the solutions to the equation x^2+3x-130=0 ?
The solutions to the equation x^2+3x-130=0 are x=10,x=-13
Find the zeros of x^2+3x-130=0
The zeros of x^2+3x-130=0 are x=10,x=-13