What are the solutions to the equation -49/16+15/2 =d^2 ?

The solutions to the equation -49/16+15/2 =d^2 are d=(sqrt(71))/4 ,d=-(sqrt(71))/4

Find the zeros of -49/16+15/2 =d^2

The zeros of -49/16+15/2 =d^2 are d=(sqrt(71))/4 ,d=-(sqrt(71))/4

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- \frac{49}{16} + \frac{15}{2} = d^{2}

d = \frac{71}{4}, d = - \frac{71}{4}

Decimal Notation

d = 2.10653 \dots, d = - 2.10653 \dots

Solution steps

- \frac{49}{16} + \frac{15}{2} = d^{2}

Switch sides

d^{2} = - \frac{49}{16} + \frac{15}{2}

Simplify

- \frac{49}{16} + \frac{15}{2} : \frac{71}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

d = \frac{71}{16}, d = - \frac{71}{16}

\frac{71}{16} = \frac{71}{4}

- \frac{71}{16} = - \frac{71}{4}

d = \frac{71}{4}, d = - \frac{71}{4}

12 x y + 21 x yz + 45 x z

- \frac{1}{4} \cdot 1

121 + x^{2} = 22 x

- 8 (v + 1) = 2 (1 - 4 v) - 9

x^{2} + 1 = 2 x

What are the solutions to the equation -49/16+15/2 =d^2 ?
The solutions to the equation -49/16+15/2 =d^2 are d=(sqrt(71))/4 ,d=-(sqrt(71))/4
Find the zeros of -49/16+15/2 =d^2
The zeros of -49/16+15/2 =d^2 are d=(sqrt(71))/4 ,d=-(sqrt(71))/4