What are the solutions to the equation x^2-6x+9=16 ?

The solutions to the equation x^2-6x+9=16 are x=7,x=-1

Find the zeros of x^2-6x+9=16

The zeros of x^2-6x+9=16 are x=7,x=-1

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x^{2} - 6 x + 9 = 16

x = 7, x = - 1

Solution steps

x^{2} - 6 x + 9 = 16

Move

16

to the left side

x^{2} - 6 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 7) = 8

x_{1, 2} = \frac{- ( - 6 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 8}{2 \cdot 1}

x = \frac{- ( - 6 ) + 8}{2 \cdot 1} : 7

x = \frac{- ( - 6 ) - 8}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 7, x = - 1

- 432

\frac{( \frac{x}{9 y} + \frac{1}{6 x y} )}{( \frac{1}{3 x y} )}

\frac{1}{1 - \frac{e}{π}}

x (x + 2) = 1

- \frac{1}{3} = \frac{j}{4} - \frac{10}{3}

What are the solutions to the equation x^2-6x+9=16 ?
The solutions to the equation x^2-6x+9=16 are x=7,x=-1
Find the zeros of x^2-6x+9=16
The zeros of x^2-6x+9=16 are x=7,x=-1