What are the solutions to the equation X^2-5X-6=0 ?

The solutions to the equation X^2-5X-6=0 are X=6,X=-1

Find the zeros of X^2-5X-6=0

The zeros of X^2-5X-6=0 are X=6,X=-1

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X^{2} - 5 X - 6 = 0

X = 6, X = - 1

Solution steps

X^{2} - 5 X - 6 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 6) = 7

X_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 1}, X_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 1}

X = \frac{- ( - 5 ) + 7}{2 \cdot 1} : 6

X = \frac{- ( - 5 ) - 7}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

X = 6, X = - 1

2 (x - 1) - \frac{3 ( x + 1 )}{6} = 6 (x + 2) + 9 x - \frac{7}{2}

t^{4} - 10 t^{2} + 9 \leq 0

- 6 x + 39 = 7 x

3 x^{2} + 2 = 5 x

- 6 x^{2} = - 9 x + 7

What are the solutions to the equation X^2-5X-6=0 ?
The solutions to the equation X^2-5X-6=0 are X=6,X=-1
Find the zeros of X^2-5X-6=0
The zeros of X^2-5X-6=0 are X=6,X=-1