What are the solutions to the equation (x^2)/2+x/(20)= 1/10 ?

The solutions to the equation (x^2)/2+x/(20)= 1/10 are x= 2/5 ,x=-1/2

Find the zeros of (x^2)/2+x/(20)= 1/10

The zeros of (x^2)/2+x/(20)= 1/10 are x= 2/5 ,x=-1/2

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\frac{x ^{2}}{2} + \frac{x}{20} = \frac{1}{10}

x = \frac{2}{5}, x = - \frac{1}{2}

Decimal Notation

x = 0.4, x = - 0.5

Solution steps

\frac{x ^{2}}{2} + \frac{x}{20} = \frac{1}{10}

Find Least Common Multiplier of

2, 20, 10 : 20

Multiply by LCM=

20

\frac{x ^{2}}{2} \cdot 20 + \frac{x}{20} \cdot 20 = \frac{1}{10} \cdot 20

Simplify

10 x^{2} + x = 2

Move

2

to the left side

10 x^{2} + x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 10 ( - 2 )}{2 \cdot 10}

1^{2} - 4 \cdot 10 (- 2) = 9

x_{1, 2} = \frac{- 1 \pm 9}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 1 + 9}{2 \cdot 10}, x_{2} = \frac{- 1 - 9}{2 \cdot 10}

x = \frac{- 1 + 9}{2 \cdot 10} : \frac{2}{5}

x = \frac{- 1 - 9}{2 \cdot 10} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{2}{5}, x = - \frac{1}{2}

(3 - x)^{2} (x - \frac{7}{2}) < 0

2 x^{2} - 15 x + 8 = 0

x + 8 \leq 3 x + 1

(- 2)^{2} - 3 \leq \frac{2 x - 1}{4} \leq 3!

∣ - 2 x + 2 ∣ = - x + 10

What are the solutions to the equation (x^2)/2+x/(20)= 1/10 ?
The solutions to the equation (x^2)/2+x/(20)= 1/10 are x= 2/5 ,x=-1/2
Find the zeros of (x^2)/2+x/(20)= 1/10
The zeros of (x^2)/2+x/(20)= 1/10 are x= 2/5 ,x=-1/2