What is (-2)^2-3<= (2x-1)/4 <= 3! ?

The solution to (-2)^2-3<= (2x-1)/4 <= 3! is 5/2 <= x<= 25/2

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(-2)^2-3<= (2x-1)/4 <= 3!

(- 2)^{2} - 3 \leq \frac{2 x - 1}{4} \leq 3!

\frac{5}{2} \leq x \leq \frac{25}{2}

Interval Notation

[\frac{5}{2}, \frac{25}{2}]

Decimal Notation

2.5 \leq x \leq 12.5

Solution steps

(- 2)^{2} - 3 \leq \frac{2 x - 1}{4} \leq 3!

a \leq u \leq b

then

a \leq u and u \leq b

(- 2)^{2} - 3 \leq \frac{2 x - 1}{4} and \frac{2 x - 1}{4} \leq 3!

(- 2)^{2} - 3 \leq \frac{2 x - 1}{4} : x \geq \frac{5}{2}

\frac{2 x - 1}{4} \leq 3! : x \leq \frac{25}{2}

Combine the intervals

x \geq \frac{5}{2} and x \leq \frac{25}{2}

Merge Overlapping Intervals

\frac{5}{2} \leq x \leq \frac{25}{2}

∣ - 2 x + 2 ∣ = - x + 10

- 4 - 2

3 x^{2} - 12 x y - 5 x + 20 y

- 1 + \frac{5}{6} (- 6 x - 3) - x > - x

\frac{b}{2} - 1 \geq 1

What is (-2)^2-3<= (2x-1)/4 <= 3! ?
The solution to (-2)^2-3<= (2x-1)/4 <= 3! is 5/2 <= x<= 25/2