What are the solutions to the equation x^2+4x-64=4x ?

The solutions to the equation x^2+4x-64=4x are x=8,x=-8

Find the zeros of x^2+4x-64=4x

The zeros of x^2+4x-64=4x are x=8,x=-8

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x^{2} + 4 x - 64 = 4 x

x = 8, x = - 8

Solution steps

x^{2} + 4 x - 64 = 4 x

Move

64

to the right side

x^{2} + 4 x = 4 x + 64

Move

4 x

to the left side

x^{2} = 64

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 64, x = - 64

64 = 8

- 64 = - 8

x = 8, x = - 8

x^{2} + 9 x = 10

x^{8} y^{18}

8 x^{2} + 2 x - 6

\frac{1}{5} x < - 1 or 2 x > 0

- \frac{3}{4} x \geq - \frac{5}{12} + \frac{1}{3} x

What are the solutions to the equation x^2+4x-64=4x ?
The solutions to the equation x^2+4x-64=4x are x=8,x=-8
Find the zeros of x^2+4x-64=4x
The zeros of x^2+4x-64=4x are x=8,x=-8