What are the solutions to the equation x^2+169=0 ?

The solutions to the equation x^2+169=0 are x=13i,x=-13i

Find the zeros of x^2+169=0

The zeros of x^2+169=0 are x=13i,x=-13i

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x^{2} + 169 = 0

x = 13 i, x = - 13 i

Solution steps

x^{2} + 169 = 0

Move

169

to the right side

x^{2} = - 169

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 169, x = - - 169

- 169 = 13 i

- - 169 = - 13 i

x = 13 i, x = - 13 i

(- 27)^{\frac{- 2}{3}}

(x^{2} + x - 6) (2 x^{2} + 4 x)

\frac{5}{8} + \frac{1}{2}

\frac{125 x ^{3} y ^{6}}{5 x ^{8} y ^{7}}

\frac{1}{x} > 4

What are the solutions to the equation x^2+169=0 ?
The solutions to the equation x^2+169=0 are x=13i,x=-13i
Find the zeros of x^2+169=0
The zeros of x^2+169=0 are x=13i,x=-13i