What are the solutions to the equation x^2+14x-27=8 ?

The solutions to the equation x^2+14x-27=8 are x=-7+2sqrt(21),x=-7-2sqrt(21)

Find the zeros of x^2+14x-27=8

The zeros of x^2+14x-27=8 are x=-7+2sqrt(21),x=-7-2sqrt(21)

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x^{2} + 14 x - 27 = 8

x = - 7 + 221, x = - 7 - 221

Decimal Notation

x = 2.16515 \dots, x = - 16.16515 \dots

Solution steps

x^{2} + 14 x - 27 = 8

Move

8

to the left side

x^{2} + 14 x - 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot ( - 35 )}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot (- 35) = 421

x_{1, 2} = \frac{- 14 \pm 4 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 4 21}{2 \cdot 1}, x_{2} = \frac{- 14 - 4 21}{2 \cdot 1}

x = \frac{- 14 + 4 21}{2 \cdot 1} : - 7 + 221

x = \frac{- 14 - 4 21}{2 \cdot 1} : - 7 - 221

The solutions to the quadratic equation are:

x = - 7 + 221, x = - 7 - 221

\frac{2 x - 7}{3} - 1 = \frac{x - 4}{6}

3 \cdot 9

8.3 (x - 3.1) = - 37.35

\frac{7 ^{- 2} m ^{0}}{n ^{- 4}}

(- 3 x y^{5})^{2} (x^{3} y)^{- 1}

What are the solutions to the equation x^2+14x-27=8 ?
The solutions to the equation x^2+14x-27=8 are x=-7+2sqrt(21),x=-7-2sqrt(21)
Find the zeros of x^2+14x-27=8
The zeros of x^2+14x-27=8 are x=-7+2sqrt(21),x=-7-2sqrt(21)