What are the solutions to the equation 5v^2-21=10v ?

The solutions to the equation 5v^2-21=10v are v=(5+sqrt(130))/5 ,v=(5-sqrt(130))/5

Find the zeros of 5v^2-21=10v

The zeros of 5v^2-21=10v are v=(5+sqrt(130))/5 ,v=(5-sqrt(130))/5

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5 v^{2} - 21 = 10 v

v = \frac{5 + 130}{5}, v = \frac{5 - 130}{5}

Decimal Notation

v = 3.28035 \dots, v = - 1.28035 \dots

Solution steps

5 v^{2} - 21 = 10 v

Move

10 v

to the left side

5 v^{2} - 21 - 10 v = 0

Write in the standard form

a x^{2} + b x + c = 0

5 v^{2} - 10 v - 21 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 5 ( - 21 )}{2 \cdot 5}

(- 10)^{2} - 4 \cdot 5 (- 21) = 2130

v_{1, 2} = \frac{- ( - 10 ) \pm 2 130}{2 \cdot 5}

Separate the solutions

v_{1} = \frac{- ( - 10 ) + 2 130}{2 \cdot 5}, v_{2} = \frac{- ( - 10 ) - 2 130}{2 \cdot 5}

v = \frac{- ( - 10 ) + 2 130}{2 \cdot 5} : \frac{5 + 130}{5}

v = \frac{- ( - 10 ) - 2 130}{2 \cdot 5} : \frac{5 - 130}{5}

The solutions to the quadratic equation are:

v = \frac{5 + 130}{5}, v = \frac{5 - 130}{5}

x^{6} - 8 y^{6}

64 a^{3} + 20 a - 125 b^{3} - 25 b

2 x^{2} - 2 x - 5 = 0

5 x + 3 = - 3 x - 1

\frac{n - 9}{n + 9} - \frac{n - 10}{n + 8}

What are the solutions to the equation 5v^2-21=10v ?
The solutions to the equation 5v^2-21=10v are v=(5+sqrt(130))/5 ,v=(5-sqrt(130))/5
Find the zeros of 5v^2-21=10v
The zeros of 5v^2-21=10v are v=(5+sqrt(130))/5 ,v=(5-sqrt(130))/5