What are the solutions to the equation s^2+s+1=0 ?

The solutions to the equation s^2+s+1=0 are s=-1/2+i(sqrt(3))/2 ,s=-1/2-i(sqrt(3))/2

Find the zeros of s^2+s+1=0

The zeros of s^2+s+1=0 are s=-1/2+i(sqrt(3))/2 ,s=-1/2-i(sqrt(3))/2

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s^{2} + s + 1 = 0

s = - \frac{1}{2} + i \frac{3}{2}, s = - \frac{1}{2} - i \frac{3}{2}

Solution steps

s^{2} + s + 1 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 1 : 3 i

s_{1, 2} = \frac{- 1 \pm 3 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 1 + 3 i}{2 \cdot 1}, s_{2} = \frac{- 1 - 3 i}{2 \cdot 1}

s = \frac{- 1 + 3 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{3}{2}

s = \frac{- 1 - 3 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

s = - \frac{1}{2} + i \frac{3}{2}, s = - \frac{1}{2} - i \frac{3}{2}

m^{2} - 8 m + 7

8 f = 64

3 r - 5 = 2 r

34 + 12 d > 100

x^{2} - 0.95 x + 0.12 = 0

What are the solutions to the equation s^2+s+1=0 ?
The solutions to the equation s^2+s+1=0 are s=-1/2+i(sqrt(3))/2 ,s=-1/2-i(sqrt(3))/2
Find the zeros of s^2+s+1=0
The zeros of s^2+s+1=0 are s=-1/2+i(sqrt(3))/2 ,s=-1/2-i(sqrt(3))/2