What are the solutions to the equation 16x^2-56x=-51 ?

The solutions to the equation 16x^2-56x=-51 are x= 7/4+i(sqrt(2))/4 ,x= 7/4-i(sqrt(2))/4

Find the zeros of 16x^2-56x=-51

The zeros of 16x^2-56x=-51 are x= 7/4+i(sqrt(2))/4 ,x= 7/4-i(sqrt(2))/4

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16 x^{2} - 56 x = - 51

x = \frac{7}{4} + i \frac{2}{4}, x = \frac{7}{4} - i \frac{2}{4}

Solution steps

16 x^{2} - 56 x = - 51

Move

51

to the left side

16 x^{2} - 56 x + 51 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 56 ) \pm ( - 56 ) ^{2} - 4 \cdot 16 \cdot 51}{2 \cdot 16}

Simplify

(- 56)^{2} - 4 \cdot 16 \cdot 51 : 82 i

x_{1, 2} = \frac{- ( - 56 ) \pm 8 2 i}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- ( - 56 ) + 8 2 i}{2 \cdot 16}, x_{2} = \frac{- ( - 56 ) - 8 2 i}{2 \cdot 16}

x = \frac{- ( - 56 ) + 8 2 i}{2 \cdot 16} : \frac{7}{4} + i \frac{2}{4}

x = \frac{- ( - 56 ) - 8 2 i}{2 \cdot 16} : \frac{7}{4} - i \frac{2}{4}

The solutions to the quadratic equation are:

x = \frac{7}{4} + i \frac{2}{4}, x = \frac{7}{4} - i \frac{2}{4}

(- \frac{3}{5})^{2} + y^{2} = 1

3 (x - 7) = 5 (x - 1) - 4

2 - 23

\frac{k + 1}{k + 2} + \frac{1}{( k + 1 ) ( k + 2 )}

2 x < 3 x + 2 < x + 6

What are the solutions to the equation 16x^2-56x=-51 ?
The solutions to the equation 16x^2-56x=-51 are x= 7/4+i(sqrt(2))/4 ,x= 7/4-i(sqrt(2))/4
Find the zeros of 16x^2-56x=-51
The zeros of 16x^2-56x=-51 are x= 7/4+i(sqrt(2))/4 ,x= 7/4-i(sqrt(2))/4