What are the solutions to the equation 96x-16x^2=0 ?

The solutions to the equation 96x-16x^2=0 are x=0,x=6

Find the zeros of 96x-16x^2=0

The zeros of 96x-16x^2=0 are x=0,x=6

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96 x - 16 x^{2} = 0

x = 0, x = 6

Solution steps

96 x - 16 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 16 x^{2} + 96 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 96 \pm 9 6 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

9 6^{2} - 4 (- 16) \cdot 0 = 96

x_{1, 2} = \frac{- 96 \pm 96}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- 96 + 96}{2 ( - 16 )}, x_{2} = \frac{- 96 - 96}{2 ( - 16 )}

x = \frac{- 96 + 96}{2 ( - 16 )} : 0

x = \frac{- 96 - 96}{2 ( - 16 )} : 6

The solutions to the quadratic equation are:

x = 0, x = 6

∣ 4 - 7 ∣

6 (u + 2) = - 2 (8 u - 3) + 4 u

1 0^{2} + 2 4^{2} = c^{2}

9^{2} + 7^{2} = c^{2}

5 a (- 3 b) (- 2 a^{2} b^{3})

What are the solutions to the equation 96x-16x^2=0 ?
The solutions to the equation 96x-16x^2=0 are x=0,x=6
Find the zeros of 96x-16x^2=0
The zeros of 96x-16x^2=0 are x=0,x=6