What are the solutions to the equation 0=x^2-8x+13 ?

The solutions to the equation 0=x^2-8x+13 are x=4+sqrt(3),x=4-sqrt(3)

Find the zeros of 0=x^2-8x+13

The zeros of 0=x^2-8x+13 are x=4+sqrt(3),x=4-sqrt(3)

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0 = x^{2} - 8 x + 13

x = 4 + 3, x = 4 - 3

Solution steps

0 = x^{2} - 8 x + 13

Switch sides

x^{2} - 8 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 13 = 23

x_{1, 2} = \frac{- ( - 8 ) \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 3}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 3}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 3}{2 \cdot 1} : 4 + 3

x = \frac{- ( - 8 ) - 2 3}{2 \cdot 1} : 4 - 3

The solutions to the quadratic equation are:

x = 4 + 3, x = 4 - 3

2 x + 24 = \frac{2}{7} x

6 x^{2} + 3 x = 0

(- 3)^{3}

x^{2} + 12 \geq 7 x

6 x + 7 - x^{2} = 0

What are the solutions to the equation 0=x^2-8x+13 ?
The solutions to the equation 0=x^2-8x+13 are x=4+sqrt(3),x=4-sqrt(3)
Find the zeros of 0=x^2-8x+13
The zeros of 0=x^2-8x+13 are x=4+sqrt(3),x=4-sqrt(3)