What are the solutions to the equation 4x^2+14x=5 ?

The solutions to the equation 4x^2+14x=5 are x=(-7+sqrt(69))/4 ,x=-(7+sqrt(69))/4

Find the zeros of 4x^2+14x=5

The zeros of 4x^2+14x=5 are x=(-7+sqrt(69))/4 ,x=-(7+sqrt(69))/4

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4 x^{2} + 14 x = 5

x = \frac{- 7 + 69}{4}, x = - \frac{7 + 69}{4}

Decimal Notation

x = 0.32665 \dots, x = - 3.82665 \dots

Solution steps

4 x^{2} + 14 x = 5

Move

5

to the left side

4 x^{2} + 14 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 4 ( - 5 )}{2 \cdot 4}

1 4^{2} - 4 \cdot 4 (- 5) = 269

x_{1, 2} = \frac{- 14 \pm 2 69}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 14 + 2 69}{2 \cdot 4}, x_{2} = \frac{- 14 - 2 69}{2 \cdot 4}

x = \frac{- 14 + 2 69}{2 \cdot 4} : \frac{- 7 + 69}{4}

x = \frac{- 14 - 2 69}{2 \cdot 4} : - \frac{7 + 69}{4}

The solutions to the quadratic equation are:

x = \frac{- 7 + 69}{4}, x = - \frac{7 + 69}{4}

(x - 3)^{2} (2 x + 1)^{3} + (x - 3)^{3} (2 x + 1)^{2}

4 x + 5 < x^{2}

(\frac{9}{20} d^{5}) (2 d^{- 2}) (\frac{4}{3} d^{9})

0. 5^{0.5}

(- 3 + i) (- 3 - i)

What are the solutions to the equation 4x^2+14x=5 ?
The solutions to the equation 4x^2+14x=5 are x=(-7+sqrt(69))/4 ,x=-(7+sqrt(69))/4
Find the zeros of 4x^2+14x=5
The zeros of 4x^2+14x=5 are x=(-7+sqrt(69))/4 ,x=-(7+sqrt(69))/4