What are the solutions to the equation 10x^2-x-24=0 ?

The solutions to the equation 10x^2-x-24=0 are x= 8/5 ,x=-3/2

Find the zeros of 10x^2-x-24=0

The zeros of 10x^2-x-24=0 are x= 8/5 ,x=-3/2

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10 x^{2} - x - 24 = 0

x = \frac{8}{5}, x = - \frac{3}{2}

Decimal Notation

x = 1.6, x = - 1.5

Solution steps

10 x^{2} - x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 10 ( - 24 )}{2 \cdot 10}

(- 1)^{2} - 4 \cdot 10 (- 24) = 31

x_{1, 2} = \frac{- ( - 1 ) \pm 31}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 31}{2 \cdot 10}, x_{2} = \frac{- ( - 1 ) - 31}{2 \cdot 10}

x = \frac{- ( - 1 ) + 31}{2 \cdot 10} : \frac{8}{5}

x = \frac{- ( - 1 ) - 31}{2 \cdot 10} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{8}{5}, x = - \frac{3}{2}

6 r^{2} + 6 r + 12 = 0

3 k + 12 \leq 6

\frac{5}{12}

6 x^{5} + 18 x^{3} - 24 x^{2}

u^{2} + 8 u + 16 = 0

What are the solutions to the equation 10x^2-x-24=0 ?
The solutions to the equation 10x^2-x-24=0 are x= 8/5 ,x=-3/2
Find the zeros of 10x^2-x-24=0
The zeros of 10x^2-x-24=0 are x= 8/5 ,x=-3/2