What is factor 5x^2+20xy+20y^2 ?

The solution to factor 5x^2+20xy+20y^2 is 5(x+2y)^2

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factor 5x^2+20xy+20y^2

factor

5 x^{2} + 20 x y + 20 y^{2}

5 (x + 2 y)^{2}

Solution steps

5 x^{2} + 20 x y + 20 y^{2}

Factor out common term

5 : 5 (x^{2} + 4 x y + 4 y^{2})

= 5 (x^{2} + 4 x y + 4 y^{2})

Factor

x^{2} + 4 x y + 4 y^{2} : (x + 2 y) (x + 2 y)

= 5 (x + 2 y) (x + 2 y)

Apply exponent rule:

aa = a^{2}

(x + 2 y) (x + 2 y) = (x + 2 y)^{2}

= 5 (x + 2 y)^{2}

\frac{x ^{2} + x - 6}{x - 7} \leq 0

3 x^{2} + 24 x + 48

4 x^{2} + 3 x - 7 = 0

x^{2} - 2 x + 7 = 0

(\frac{3 x ^{4}}{2 y ^{5}})^{- 3}

What is factor 5x^2+20xy+20y^2 ?
The solution to factor 5x^2+20xy+20y^2 is 5(x+2y)^2