What is factor t^2+8t+12 ?

The solution to factor t^2+8t+12 is (t+2)(t+6)

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factor t^2+8t+12

factor

t^{2} + 8 t + 12

(t + 2) (t + 6)

Solution steps

t^{2} + 8 t + 12

Break the expression into groups

= (t^{2} + 2 t) + (6 t + 12)

Factor out

t

from

t^{2} + 2 t : t (t + 2)

Factor out

6

from

6 t + 12 : 6 (t + 2)

= t (t + 2) + 6 (t + 2)

Factor out common term

t + 2

= (t + 2) (t + 6)

x - 6 < 2 (x - 15)

\frac{1}{2} (x + 5) - 4 = \frac{1}{3} (2 x - 1)

2 a - 8

2 (a - 1) = 3 (a + 1)

3 x^{2} + 2 x + 3 = 0