What are the solutions to the equation 7^2+b^2=25^2 ?

The solutions to the equation 7^2+b^2=25^2 are b=24,b=-24

Find the zeros of 7^2+b^2=25^2

The zeros of 7^2+b^2=25^2 are b=24,b=-24

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7^{2} + b^{2} = 2 5^{2}

b = 24, b = - 24

Solution steps

7^{2} + b^{2} = 2 5^{2}

Move

7^{2}

to the right side

b^{2} = 576

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 576, b = - 576

576 = 24

- 576 = - 24

b = 24, b = - 24

4 x + 2 + x^{2} = 0

2 x^{3} - x^{4} \leq 0

lo g_{\frac{1}{4}} (\frac{1}{16})

\frac{a ^{3} - b ^{3}}{( a - b ) ^{2}} + \frac{3 ab}{b - a}

10 x^{2} + 13 x + 4 = 0

What are the solutions to the equation 7^2+b^2=25^2 ?
The solutions to the equation 7^2+b^2=25^2 are b=24,b=-24
Find the zeros of 7^2+b^2=25^2
The zeros of 7^2+b^2=25^2 are b=24,b=-24