What are the solutions to the equation x^2-20x=5 ?

The solutions to the equation x^2-20x=5 are x=10+sqrt(105),x=10-sqrt(105)

Find the zeros of x^2-20x=5

The zeros of x^2-20x=5 are x=10+sqrt(105),x=10-sqrt(105)

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x^{2} - 20 x = 5

x = 10 + 105, x = 10 - 105

Decimal Notation

x = 20.24695 \dots, x = - 0.24695 \dots

Solution steps

x^{2} - 20 x = 5

Move

5

to the left side

x^{2} - 20 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 20)^{2} - 4 \cdot 1 \cdot (- 5) = 2105

x_{1, 2} = \frac{- ( - 20 ) \pm 2 105}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 2 105}{2 \cdot 1}, x_{2} = \frac{- ( - 20 ) - 2 105}{2 \cdot 1}

x = \frac{- ( - 20 ) + 2 105}{2 \cdot 1} : 10 + 105

x = \frac{- ( - 20 ) - 2 105}{2 \cdot 1} : 10 - 105

The solutions to the quadratic equation are:

x = 10 + 105, x = 10 - 105

∣ 7.5 - 82 x ∣ \geq - 17

16 a^{4} - b^{4}

\frac{1}{x}

x - 4 [x - 2 (x + 6)] = 5 x + 3

\frac{1}{\frac{5}{\frac{7}{8} - \frac{1}{2}}} + \frac{1}{20}

What are the solutions to the equation x^2-20x=5 ?
The solutions to the equation x^2-20x=5 are x=10+sqrt(105),x=10-sqrt(105)
Find the zeros of x^2-20x=5
The zeros of x^2-20x=5 are x=10+sqrt(105),x=10-sqrt(105)