What are the solutions to the equation (2x-4)^2=26 ?

The solutions to the equation (2x-4)^2=26 are x=(sqrt(26)+4)/2 ,x=(-sqrt(26)+4)/2

Find the zeros of (2x-4)^2=26

The zeros of (2x-4)^2=26 are x=(sqrt(26)+4)/2 ,x=(-sqrt(26)+4)/2

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(2 x - 4)^{2} = 26

x = \frac{26 + 4}{2}, x = \frac{- 26 + 4}{2}

Decimal Notation

x = 4.54950 \dots, x = - 0.54950 \dots

Solution steps

(2 x - 4)^{2} = 26

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 4 = 26 : x = \frac{26 + 4}{2}

Solve

2 x - 4 = - 26 : x = \frac{- 26 + 4}{2}

The solutions to the quadratic equation are:

x = \frac{26 + 4}{2}, x = \frac{- 26 + 4}{2}

3 x + 8 < 15

x^{2} = - 245

x^{3} - x \leq 0

∣ 2 x + 3 ∣ \geq 5

- 3 (3 y - 2) < 1 - 9 y

What are the solutions to the equation (2x-4)^2=26 ?
The solutions to the equation (2x-4)^2=26 are x=(sqrt(26)+4)/2 ,x=(-sqrt(26)+4)/2
Find the zeros of (2x-4)^2=26
The zeros of (2x-4)^2=26 are x=(sqrt(26)+4)/2 ,x=(-sqrt(26)+4)/2