What are the solutions to the equation 4m^2+m=0 ?

The solutions to the equation 4m^2+m=0 are m=0,m=-1/4

Find the zeros of 4m^2+m=0

The zeros of 4m^2+m=0 are m=0,m=-1/4

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4 m^{2} + m = 0

m = 0, m = - \frac{1}{4}

Decimal Notation

m = 0, m = - 0.25

Solution steps

4 m^{2} + m = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

1^{2} - 4 \cdot 4 \cdot 0 = 1

m_{1, 2} = \frac{- 1 \pm 1}{2 \cdot 4}

Separate the solutions

m_{1} = \frac{- 1 + 1}{2 \cdot 4}, m_{2} = \frac{- 1 - 1}{2 \cdot 4}

m = \frac{- 1 + 1}{2 \cdot 4} : 0

m = \frac{- 1 - 1}{2 \cdot 4} : - \frac{1}{4}

The solutions to the quadratic equation are:

m = 0, m = - \frac{1}{4}

∣ 2 (x - 1) + 4 ∣ \leq 8

- 5 i \cdot (5 i - 5)

(2 w + 11) w = 63

\frac{6}{4} = \frac{x}{6}

x^{5} - y^{5}

What are the solutions to the equation 4m^2+m=0 ?
The solutions to the equation 4m^2+m=0 are m=0,m=-1/4
Find the zeros of 4m^2+m=0
The zeros of 4m^2+m=0 are m=0,m=-1/4