What is -8<= 4x-7<= 6 ?

The solution to -8<= 4x-7<= 6 is -1/4 <= x<= 13/4

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-8<= 4x-7<= 6

- 8 \leq 4 x - 7 \leq 6

- \frac{1}{4} \leq x \leq \frac{13}{4}

Interval Notation

[- \frac{1}{4}, \frac{13}{4}]

Decimal Notation

- 0.25 \leq x \leq 3.25

Solution steps

- 8 \leq 4 x - 7 \leq 6

a \leq u \leq b

then

a \leq u and u \leq b

- 8 \leq 4 x - 7 and 4 x - 7 \leq 6

- 8 \leq 4 x - 7 : x \geq - \frac{1}{4}

4 x - 7 \leq 6 : x \leq \frac{13}{4}

Combine the intervals

x \geq - \frac{1}{4} and x \leq \frac{13}{4}

Merge Overlapping Intervals

- \frac{1}{4} \leq x \leq \frac{13}{4}

\frac{3}{4} \cdot \frac{4}{7}

3 6^{\frac{5}{2}}

x (- 2 x - 13) = - 1

x^{2} - 8 x + 21 = 0

4 y = y^{2} - 12